2.50 x 104 2.5 x 10-7 2.5 x 10-4 2.5 x 10-3 2.50 x 10-3 none of these
(13.6 x 454 x 1000 x 3.7854)/4 (13.6 x 1000 x 3.7854)/(454 x 4) (13.6 x 3.7854)/(454 x 1000 x 4) (13.6 x 1000 x 4)/(454 x 3.7854) (13.6 x 454 x 3.7854)/(1000 x 4) none of these
(11.4 x 1000)/3.7854 (11.4 x 3.7854)/1000 11.4 x 3.7854 x 1000 11.4/(3.7854 x 1000) 11.4 x 3.7854 x 100 none of these
10 micrograms and 0.1 milligrams 10 nL and 1000 pL 40 km and 40000 cm 0.01 mm and 1 x 10-3 cm all of these none of these
2 and 3 1 and 2 1 and 3 all are valid none are valid
Rb, Y, I Ba, Fe, Br Sr, Zr, Xe K, Ni, O none of these all of these
1 and 3 2 only 3 only 1 and 2 1 only 2 and 3
alpha particles must be ricocheting off the electrons all of the positive charge and most of the mass of the atom is concentrated in a tiny kernel atoms were indestructible and reflected alpha particles alpha particles were annhilating the metal atoms Thomson's plum pudding model was valid none of the above
81Br has two more electrons than 79Br. 81Br has two more protons than 79Br. 81Br has two more neutrons than 79Br. 79Br has 79 neutrons. 79Br has 35 electrons and 44 protons. none of these
36Cl 37Cl 38Cl 34Cl 35.453Cl none of these
Cu(HCO3)2, copper (II) bicarbonate Ba3(PO4)2, tribarium diphosphate AgNO3, argentum nitrate SrSO3, strontium sulfate FeCO3, iron (III) carbonate none of these
CdSe2 Cd2Se CdSe Cd2Se2 Cd-II-Se none of these
HS H2S H2SO2 H2SO3 H2SO4 HSO4
C6H12O6(s) + O2(g) = CO2(g) + H2O(l)
18 9 6 12 15 none of these
none of these HNO3(aq) and Sr(OH)2(aq) NaOH and KBr Zn and HCl AgNO3 and NaClO4 Na2SO4(aq) and Ba(OH)2(aq)
H3O+(aq) HC2H3O2(aq) C2H3O2-(aq) all of these OH-(aq) H2O(l)
HCl(aq) + KOH(aq) = H2O(l) + KCl(aq) K+(aq) + Cl-(aq) = KCl(aq) K+(aq) + Cl-(aq) = KCl(s) K+(aq) + Cl-(aq) + H+(aq) + OH-(aq) = H2O(l) + K+(aq) + Cl-(aq) H3O+(aq) + OH-(aq) = 2 H2O(l) HClO4(aq) + KOH(aq) = H2O(l) + KClO4(aq)
LiBr NaNO3(aq) KC2H3O2(aq) AgNO3(aq) acetic acid none of these
43.8% 35.4% 17.5% 42.9% 35.0% none of these
SO SO4 SO2 S2O3 SO3 none of these
4 Mn(OH)2(aq) + O2(aq) + 2 H2O(aq) = 4 Mn(OH)3(s)
(0.103 x 32)/(88.94 x 4) (0.103 x 105.94 x 32)/4 (0.103 x 4 x 32)/105.94 (0.103 x 16)/(105.94 x 4) (0.103 x 32)/(105.94 x 4) (0.103 x 16)/(88.94 x 4)
C6H12O6 C12H24O12 C360H720O360 CH2O C12H12O12 none of these
3 O2(g) = 2 O3(g)
1.5 g 0.04 g 1 g 25 g 0.06 g none of these
Copyright © 1997,1998 by Fred Senese Comments & questions to senese@antoine.frostburg.edu Last Revised 02/23/18. URL: http://antoine.frostburg.edu/chem/senese/101/101-sample-exam-1a.shtml