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How do I balance the equation for combustion of Si2H6?
- How was this answer arrived at: 2 Si2H6 + 7 O2 4 SiO2 + 6 H2O
For more about the individual steps I used, see 10 tips for balancing simple equations.
- First, I'm going to try putting a 1 in front of the most complicated looking compound.
1 Si2H6 + O2 SiO2 + H2O
- To balance the Si's, I must put a 2 in front of the SiO2. That gives me 2 silicon atoms on each side.
1 Si2H6 + O2 2 SiO2 + H2O
- To balance the H's, I must put a 3 in front of the H2O. That gives me 6 hydrogen atoms on each side.
1 Si2H6 + O2 2 SiO2 + 3 H2O
- The right side has 7 oxygens. I'll write 7/2 in front of O2 to give me 7 oxygens on the left side.
1 Si2H6 + 7/2 O2 2 SiO2 + 3 H2O
- I'll multiply everything through by 2 to get rid of the fraction.
This isn't really necessary; the equation would be correctly balanced with fractional coefficients!
2 Si2H6 + 7 O2 4 SiO2 + 6 H2O
Author: Fred Senese firstname.lastname@example.org