q(iron) + q(water) + q(calorimeter) = 0
This is an approximation. When an object warms, it expands, and it has to push against the atmosphere to do that. That work against the atmosphere involves a bit of energy that should be included in the equation. We ignore it because it's small in this case and it's much simpler to leave it out. the things that are mentioned in the problem.
m(iron) c(iron) T(iron) + m(water) c(water) T(water) + C(calorimeter) T(calorimeter) = 0You can see that you'll need to look up the specific heat of iron and of water to finish the problem.
Author: Fred Senese email@example.com
Copyright © 1997-2010 by Fred Senese
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Last Revised 08/17/15.URL: http://antoine.frostburg.edu/chem/senese/101/thermo/faq/print-calorimeter-constant.shtml