| Vocabulary | |
endothermic![]() enthalpy ![]() enthalpy of hydration ![]() exothermic ![]() Hess's law ![]() redox ![]() spontaneous ![]() sublimation ![]() |
Cu(s) + Zn2+(aq) is spontaneous and exothermic. To figure out exactly where the heat released comes from, we'll have to break the reaction down into simpler steps. Hess's law says that it doesn't matter how many
steps we chose to write; the enthalpy changes for each step will add up to the enthalpy change for the net reaction.
One possible way of analyzing the reaction involves breaking it into separate sublimation, ionization, and hydration steps:
Cu2+(aq)
Cu2+(g)
H° = +2289 kJ
Cu2+(g) + 2 e-
Cu(g)
H° = -2703.4 kJ
H is equal to minus the sum of the first and second ionization enthalpies for copper. Capture of electrons by a cation is always exothermic.
Cu(g)
Cu(s)
H° = -337.4 kJ
H for condensation of gaseous copper is minus the heat of formation for gaseous copper. The process is exothermic because strong metallic bonds are formed in the condensation.
Zn(s)
Zn(g)
H° = +130.5 kJ
Zn(g)
Zn2+(g) + 2 e-
H° = +2639 kJ
Zn2+(g)
Zn2+(aq)
H° = -2247 kJ
Zn(s) + Cu2+(aq)
Cu(s) + Zn2+(aq)
H° = -229 kJ
Although the reaction doesn't actually proceed by a series of sublimation-ionization-hydration steps,
the calculation does give us a valuable insight into where the energy is actually coming from in the reaction.
Try the following questions to explore some reasonable deductions that can be made about the significance of ion-water interactions, metallic bonding, and attraction for valence electrons in determining the sign on
H in this reaction.
Copyright © 1997-2005 by Fred Senese
Comments & questions to fsenese@frostburg.edu
Last Revised 07/31/07.URL: http://antoine.frostburg.edu/chem/senese/101/thermo/faq/print-why-are-metal-displacements-exothermic.shtml