200 mL of 0.100 M HNO3 initially 0.010 M H+ finally |
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mol HNO3 reacted | mole-to-mole ratio from balanced equation ![]() |
mol KOH |
Now you have to get moles of HNO3 reacted. Moles reacted will be final moles minus initial moles. You know initial moles of HNO3, since you know the volume and concentration of the initial HNO3 solution. You can estimate final moles too- you have to have a pH of 2.00, which is a hydrogen ion concentration of 0.010 M, and also a nitric acid concentration of 0.010 M. If you assume that the added KOH doesn't increase the volume significantly, the final volume of the solution is about 200 mL.
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Last Revised 02/23/18.URL: http://antoine.frostburg.edu/chem/senese/101/moles/faq/print-adjust-pH-HNO3-with-KOH.shtml